A bundle of 500 sheets of paper has a net weight of $2\dfrac{3}{10}$kg. Find the weight of 1 sheet of paper.

Given:

Total weigth = $2\dfrac{3}{10} \text{ kg} = \dfrac{23}{10} \text{ kg}$

Number of sheets = 500

Weigth of 1 sheet of paper = (Total weigth) ÷ (Number of sheets)

Substituting the values in above, we get:

Weigth of 1 sheet of paper = $\dfrac{23}{10}$ kg ÷ 500

$\begin{array}{ll} = \Big(\dfrac{23}{10} \times \dfrac{1}{500}\Big)\text{ kg} & [\text{Reciprocal of } 500 \text{ is } \dfrac{1}{500}] \\ = \dfrac{23 \times 1}{10 \times 500} \text{ kg} \\ = \dfrac{23}{5000} \text{ kg} \end{array}$

∴ The weigth of 1 sheet of paper = $\dfrac{23}{5000}$ kg