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Mathematics

By selling a certain number of goods for ₹ 5,500, a shopkeeper loses equal to one-tenth of their selling price. Find :

(i) the loss incurred

(ii) the cost price of the goods

(iii) the loss as percent.

Profit, Loss & Discount

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Answer

(i) Given:

S.P. of a certain number of goods = ₹ 5,500

Loss = one-tenth of its selling price

=110×5,500=5,50010=550= ₹ \dfrac{1}{10} \times 5,500\\[1em] = ₹ \dfrac{5,500}{10}\\[1em] = ₹ 550

Loss = ₹ 550

(ii) As we know that,

Loss = C.P. - S.P.

Putting the values, we get

₹ 550 = C.P. - ₹ 5,500

C.P. = ₹ 5,500 + ₹ 550

= ₹ 6,050

The cost price of the goods = ₹ 6,050.

(iii)

Loss %=LossC.P.×100%=5506050×100%=55,0006050%=10011%=9111%\text{Loss \%} = \dfrac{\text{Loss}}{\text{C.P.}} \times 100\%\\[1em] = \dfrac{550}{6050} \times 100\%\\[1em] = \dfrac{55,000}{6050}\%\\[1em] = \dfrac{100}{11}\%\\[1em] = 9\dfrac{1}{11}\%

Hence, T.V. is sold at a loss of 9111%9\dfrac{1}{11}\%.

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