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Mathematics

By selling an article at 20% discount, a shopkeeper gains 25%. If the selling price of the article is ₹ 1,440, find :

(i) the marked price of the article.

(ii) the cost price of the article.

Profit, Loss & Discount

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Answer

(i) Given:

Discount on the article = 20%

S.P. of the article = ₹ 1,440

Let the M.P. of the article be ₹xx.

As we know,

Discount%=DiscountM.P.×10020=Discountx×100Discount=20×x100Discount=20x100Discount=x5\text{Discount\%} = \dfrac{\text{Discount}}{\text{M.P.}} \times 100\\[1em] \Rightarrow 20 = \dfrac{\text{Discount}}{x} \times 100\\[1em] \Rightarrow \text{Discount} = \dfrac{20 \times x}{100}\\[1em] \Rightarrow \text{Discount} = \dfrac{20x}{100}\\[1em] \Rightarrow \text{Discount} = \dfrac{x}{5}\\[1em]

And,

Discount = M.P. - S.P.x5=x14401440=xx51440=5x5x51440=(5xx)51440=4x5x=5×1,4404x=7,2004x=1,800\text{Discount = M.P. - S.P.}\\[1em] \Rightarrow \dfrac{x}{5} = x - 1440\\[1em] \Rightarrow 1440 = x - \dfrac{x}{5}\\[1em] \Rightarrow 1440 = \dfrac{5x}{5} - \dfrac{x}{5}\\[1em] \Rightarrow 1440 = \dfrac{(5x - x)}{5} \\[1em] \Rightarrow 1440 = \dfrac{4x}{5} \\[1em] \Rightarrow x = \dfrac{5 \times 1,440}{4} \\[1em] \Rightarrow x = \dfrac{7,200}{4} \\[1em] \Rightarrow x = 1,800

Hence, M.P. of the article = ₹ 1,800

(ii) S.P. of the article = ₹ 1,440

Gain% of the article = 25%

Let the C.P. be ₹ yy.

Gain %=GainC.P.×10025=Gainy×100Gain=25×y100Gain=25y100Gain=y4\text{Gain \%} = \dfrac{\text{Gain}}{\text{C.P.}}\times 100\\[1em] \Rightarrow 25 = \dfrac{\text{Gain}}{y}\times 100\\[1em] \Rightarrow \text{Gain} = \dfrac{25 \times y}{100}\\[1em] \Rightarrow \text{Gain} = \dfrac{25y}{100}\\[1em] \Rightarrow \text{Gain} = \dfrac{y}{4}

And,

Gain = S.P. - C.P.y4=1,440yy4+y=1,440y4+4y4=1,440(y+4y)4=1,4405y4=1,440y=1,440×45y=5,7605y=1,152\text{Gain = S.P. - C.P.}\\[1em] \Rightarrow \dfrac{y}{4} = 1,440 - y\\[1em] \Rightarrow \dfrac{y}{4} + y = 1,440 \\[1em] \Rightarrow \dfrac{y}{4} + \dfrac{4y}{4} = 1,440 \\[1em] \Rightarrow \dfrac{(y + 4y)}{4} = 1,440 \\[1em] \Rightarrow \dfrac{5y}{4} = 1,440 \\[1em] \Rightarrow y = \dfrac{1,440 \times 4}{5} \\[1em] \Rightarrow y = \dfrac{5,760}{5} \\[1em] \Rightarrow y = 1,152

Hence, C.P. of the article = ₹ 1,152

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