By using standard formulae, expand the following:
(3x+12x)2\Big(3x + \dfrac{1}{2x} \Big)^2(3x+2x1)2
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(3x+12x)2=(3x)2+2(3x)(12x)+(12x)2=9x2+3+(14x2)\Big(3x + \dfrac{1}{2x} \Big)^2 = (3x)^2 + 2 (3x)\Big(\dfrac{1}{2x}\Big) + \Big(\dfrac{1}{2x}\Big)^2 \\[1em] = 9x^2 + 3 + \Big(\dfrac{1}{4x^2}\Big)(3x+2x1)2=(3x)2+2(3x)(2x1)+(2x1)2=9x2+3+(4x21)
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(2x + 7y)2
(12x+23y)2\Big(\dfrac{1}{2}x + \dfrac{2}{3}y\Big)^2(21x+32y)2
(3x2y + 5z)2
(3x−12x)2\Big(3x - \dfrac{1}{2x} \Big)^2(3x−2x1)2
