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Mathematics

Calculate the mean of the following distribution using step deviation method.

MarksNo.of students
0 – 1010
10 – 209
20 – 3025
30 – 4030
40 – 5016
50 – 6010

Measures of Central Tendency

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Answer

We construct the following table, taking assumed mean a = 25. Here, c (width of each class) = 10.

MarksNo.of studentsClass mark (yi)ui = (yi - a)/cNo. of students (fi)fi ui
0 – 10105-210-20
10 – 20915-19-9
20 – 3025a = 250250
30 – 40303513030
40 – 50164521632
50 – 60105531030
Total∑ fi = 100∑ fi ui = 63

By formula,

Mean=a+c×fiuifi=25+10×63100=25+630100=25+6.3=31.3\text{Mean} = a + c \times \dfrac{\sum fiui}{\sum f_i} \\[1em] = 25 + 10 \times \dfrac{63}{100} \\[1em] = 25 + \dfrac{630}{100} \\[1em] = 25 + 6.3 \\[1em] = 31.3

Hence, mean of the following distribution is 31.3

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