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Mathematics

Calculate the mean of the following frequency distribution.

Class-intervalFrequency
5 – 152
15 – 256
25 – 354
35 – 458
45 – 554

Measures of Central Tendency

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Answer

We construct the following table, taking assumed mean a = 30. Here, c (width of each class) = 10.

Class-intervalFrequency (fi)Class mark (yi)ui = (yi - a)/cfiui
5 – 15210-2-4
15 – 25620-1-6
25 – 354a = 3000
35 – 4584018
45 – 5545028
Total∑ fi= 24∑ fiui = 6

By formula,

Mean=a+c×fiuifi=30+10×624=30+104=30+2.5=32.5\text{Mean} = a + c \times \dfrac{\sum fiui}{\sum f_i} \\[1em] = 30 + 10 \times \dfrac{6}{24} \\[1em] = 30 + \dfrac{10}{4} \\[1em] = 30 + 2.5 \\[1em] = 32.5

Hence, mean of the frequency distribution is 32.5.

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