Calculate the number of moles and molecules in 19.86 g. of Pb(NO₃)₂. [Pb = 207, N = 14, O = 16]
Mole Concept
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Question

Calculate the number of moles and molecules in 19.86 g. of Pb(NO₃)₂. [Pb = 207, N = 14, O = 16]

KnowledgeBoat · Accepted Answer

Gram molecular mass of Pb(NO₃)₂ = Pb + 2 [N x 3(O)] = Pb + 2N + 6O = 207 + (2 x 14) + (6 x 16) = 207 + 28 + 96 = 331 As, 331 g of Pb(NO₃)₂ = 1 mole Therefore, 19.86 g Hence, number of moles in 19.86 g. of Pb(NO₃)₂ = 0.06 moles As, 1 mole of Pb(NO₃)₂ weighs 331 g and has 6.023 x 10²³ molecules Therefore, 19.86 g of Pb(NO₃)₂ will have Hence, number of molecules in 19.86 g. of Pb(NO₃)₂ = 0.06 x 6.023 x 10²³ moles

Chemistry

Calculate the number of moles and molecules in 19.86 g. of Pb(NO₃)₂. [Pb = 207, N = 14, O = 16]

Mole Concept

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