Mathematics
Calculate the sum of angles of a polygon with 10 sides:
Geometrical Shapes
11 Likes
Answer
According to the properties of a polygon, if there are n sides, then the sum of its interior angles is (2n - 4) x 90°.
For a polygon with 10 sides:
Sum of angles = (2 x 10 - 4) x 90°
= (20 - 4) x 90°
= 16 x 90°
= 1440°
Hence, sum of angles of polygon is 1440°.
Answered By
8 Likes
Related Questions
In quadrilateral ABCD, ∠D = 40°, ∠C = 80° AP bisects angle A and BP bisects angle ∠B; then ∠APB is equal:
90°
120°
90°
60°
The sum of interior angles of a polygon is 900°. The number of side in this polygon is:
5
7
9
11
Find the number of sides ina polygon if the sum of its interior angles is 16 right angles.
Is it possible to have a polygon whose sum of interior angles is:
(i) 870°
(ii) 2340°
(iii) 7 right angles ?