Chemistry
Calculate the volume of HCl gas formed and chlorine gas required when 40 ml of methane reacts completely with chlorine at STP.
CH4 + 2Cl2 ⟶ CH2Cl2 + 2HCl
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Answer
volume of HCl gas formed = ?
[By Gay Lussac's law]
1 Vol of methane produces = 2 Vol. HCl
∴ 40 ml of methane produces = 80 ml HCl
volume of chlorine gas required = ?
For 1 Vol of methane = 2V of Cl2 required
∴ for 40 ml of methane = 40 x 2 = 80 ml of Cl2 is required.
Hence, volume of HCl gas formed = 80 ml and chlorine gas required = 80 ml
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