Chemistry
Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane [C3H8].
[C = 12, O = 16, H = 1, Molar Volume = 22.4 dm3 at s.t.p.]
Stoichiometry
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Answer
(i) 44 g propane requires 5 x 22.4 lit of oxygen
∴ 8.8 g of propane will require x 8.8 = 22.4 lit.
Hence, 22.4 lit of Oxygen is required.
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