Calculate the value of A, if :

(sec 2A - 1) (cosec 3A - 1) = 0

(sec 2A - 1) (cosec 3A - 1) = 0

⇒ sec 2A - 1 = 0 and cosec 3A - 1 = 0

⇒ sec 2A = 1 and cosec 3A = 1

⇒ sec 2A = sec 0° and cosec 3A = cosec 90°

So, 2A = 0° and 3A = 90°

⇒ A = 0° and A = $\dfrac{90°}{3} = 30°$

Hence, A = 0° and 30°.