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Mathematics

A car covers 64114641\dfrac{1}{4}km in 431843\dfrac{1}{8} litres of fuel. How much distance can this car cover in 1 litre of fuel ?

Fractions

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Answer

Given:

Total distance = 64114 km=25654641\dfrac{1}{4}\text{ km} = \dfrac{2565}{4} km

Total fuel = 4318 litres=3458 litres43\dfrac{1}{8}\text{ litres} = \dfrac{345}{8}\text{ litres}

Distance per litre = ?

Distance per litre = (Total distance) ÷ (Total fuel)

Substituting the values in above, we get:

Distance per litre = 25654 km÷3458 litres\dfrac{2565}{4}\text{ km} ÷ \dfrac{345}{8}\text{ litres}

=(25654×8345) km[Reciprocal of 3458 is 8345]=(25651×2345) km[Simplifying 8 and 4 ⇒ Divide by 4]=(1711×223) km[Simplifying 2565 and 345 ⇒ Divide by 15]=171×21×23 km=34223 km=142023 km\begin{array}{ll} = \Big(\dfrac{2565}{4} \times \dfrac{8}{345}\Big)\text{ km} & [\text{Reciprocal of } \dfrac{345}{8} \text{ is } \dfrac{8}{345}] \\ = \Big(\dfrac{2565}{1} \times \dfrac{2}{345}\Big)\text{ km} & \text{[Simplifying 8 and 4 ⇒ Divide by 4]} \\ = \Big(\dfrac{171}{1} \times \dfrac{2}{23}\Big)\text{ km} & \text{[Simplifying 2565 and 345 ⇒ Divide by 15]} \\ = \dfrac{171 \times 2}{1 \times 23} \text{ km} \\ = \dfrac{342}{23} \text{ km} \\ = 14\dfrac{20}{23} \text{ km} \end{array}

∴ The distance per litre of petrol = 14202314\dfrac{20}{23} km

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