A car travelled from city A to city B with a uniform speed of $52\dfrac{2}{7}$ km per hour. Find the distance between the two cities, if it took $4\dfrac{3}{8}$ hours for the car to reach city B from city A.

Given:

Speed = $52\dfrac{2}{7}$ km/hour

Time = $4\dfrac{3}{8}$ hours

Distance = ?

We know the formula,

Distance = Speed x Time

By substituting the values we get,

$\begin{array}{ll} \text{Distance} = \Big(52\dfrac{2}{7} \times 4\dfrac{3}{8}\Big) \text{ km} & \space \\ = \Big(\dfrac{366}{7} \times \dfrac{35}{8}\Big) \text{ km} & \text{[Converting mixed to improper fraction]} \\ = \Big(\dfrac{366}{1} \times \dfrac{5}{8}\Big)\text{ km} & \text{[Simplifying 35 and 7 ⇒ Divide by 7 ]} \\ = \dfrac{366 \times 5}{1 \times 8}\text{ km} \\ = \dfrac{1830}{8} \text{ km} \\ = 228\dfrac{3}{4}\text{ km} & \text{[Converting improper to mixed fraction]} \end{array}$

∴ The distance between two cities is $228\dfrac{3}{4}$ km.