A card is drawn at random from a well-shuffled pack of 52 cards. The probability that the drawn card is neither a king nor a queen, is:

1. $\Big(\dfrac{2}{13}\Big)$

2. $\Big(\dfrac{3}{13}\Big)$

3. $\Big(\dfrac{10}{13}\Big)$

4. $\Big(\dfrac{11}{13}\Big)$

A standard deck of playing cards contains 52 cards.

Total number of outcomes = 52

There are 4 kings and 4 queens in a standard deck.

∴ Total number of kings and queens = 4 + 4 = 8.

∴ Number of cards that are neither a king nor a queen = 52 - 8 = 44.

Let E be the event of drawing a card which is neither a king nor a queen, then

The number of favorable outcomes to the event E = 44

∴ P(E) = $\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{44}{52} = \dfrac{11}{13}$

Hence, option 4 is the correct option.