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Mathematics

Cards marked with numbers 1 to 100 are placed in a box and mixed thoroughly. A card is drawn at random from the box. The probability that the selected card bears a perfect square number is:

  1. (110)\Big(\dfrac{1}{10}\Big)

  2. (225)\Big(\dfrac{2}{25}\Big)

  3. (9100)\Big(\dfrac{9}{100}\Big)

  4. (11100)\Big(\dfrac{11}{100}\Big)

Probability

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Answer

The cards are numbered from 1 to 100.

Total number of outcomes = 100

Let E be the event of getting perfect square, then

E = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

The number of favorable outcomes to the event E = 10

∴ P(E) = Number of favorable outcomesTotal number of outcomes=10100=110\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{10}{100} = \dfrac{1}{10}

Hence, option 1 is the correct option.

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