Case Study In 2015, the population of a town was 20000. During 2016 and 2017, it increases by 4% and 5% every year respectively. In 2018, due to an epidemic and migration to cities, the population decreases at 5%. Based on the above information answer the following questions: 1. The population of the town in 2016 was: (a) 20800 (b) 20500 (c) 20460 (d) 20300 2. The difference in the population of the town at the end of the years 2017 and 2015 was: (a) 1500 (b) 1700 (c) 1800 (d) 1840 3. The population of the town at the end of the year 2018 was: (a) 20100 (b) 20500 (c) 20748 (d) 20850 4. Which of the following expressions gives the population at the end of the year 2018? (a) (b) (c) (d) 5. If the population of the town at the end of 2019 was 21,163, then during 2019, the population increases at the rate of: (a) 2% (b) 3% (c) 3.5% (d) 4%

Question

KnowledgeBoat · Accepted Answer

1\. Given, Population (in 2015) = 20000 r = 4% p.a. n = 1 year By formula, Population in 2016 = Substituting the values in formula, Hence, option (a) is correct option. 2\. Given, Population (in 2016) = 20800 r = 5% p.a. n = 1 year By formula, Population in 2017 = Substituting the values in formula, The difference in population at the end of the years 2017 and 2015 = 21840 - 20000 = 1840. Hence, option (d) is correct option. 3\. Given, Population (in 2017) = 21840 r (decrease) = 5% p.a. n = 1 year By formula, Population in 2018 = Substituting the values in formula, Hence, option (c) is correct option. 4\. Given, P = ₹ 20,000 r1 = 4% r2 = 5% r3 = 5% (decrease) By formula, Population at the end = Substituting the values in formula, Hence, option (b) is correct option. 5\. Given, A (population in 2019) = 21,163 P (population in 2018) = 20,748 n = 1 year By formula, A = Substituting the values in formula, Hence, option (a) is correct option.

Mathematics

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