Mathematics

Case study:
Jasjit goes from Connaught Place to Qutub Minar, a distance of 13 km, by a taxi and after spending some time there, he returned back to Connaught Place by a route which is 16 km long in some other taxi.

Jasjit goes from Connaught Place to Qutub Minar, a distance of 13 km, by a taxi and after spending some time there, he returned back to Connaught Place by a route which is 16 km long in some other taxi. Simultaneous (Linear) Equations [Including Problems], Concise Mathematics Solutions ICSE Class 9.

Case 1: If the taxi takes a fixed charge of ₹ x and per kilometer charges as ₹ y, calculate the total fare for going from Connaught Place to Qutub Minar and then returning back.

Case 2: If the taxi takes a fixed charge of ₹ x for the first kilometer and an additional charge of for ₹ y per km for subsequent kilometers, calculate the total fare for going from Connaught Place to Qutub Minar and then returning back.

Linear Equations

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Answer

Given,

Distance (Connaught Place to Qutub Minar while going) = 13 km

Distance (Connaught Place to Qutub Minar while returning) = 16 km

Case 1:

Charges applied:

Fixed charge = ₹ x

Per km charge = ₹ y

Total fare = Fixed charge + (Distance × per km charge)

For trip while going (13 km):

Total fare = x + (13 × y) = x + 13y

For trip while returning (16 km):

Total fare = x + (16 × y) = x + 16y

Total fare of whole journey = (x + 13y) + (x + 16y)

= 2x + 29y.

Hence, total fare = ₹ (2x + 29y).

Case 2:

Charges :

Fixed charge = ₹ x for first kilometer

Per km = ₹ y for remaining distance

Going (13 km):

Charge for first km = ₹ x

Remaining distance = 12 km

Charge for remaining distance = 12y

Total fare = x + 12y

Returning (16 km):

First km = ₹ x

Remaining distance = 15 km

Charge for remaining distance = 15y

Total fare = x + 15y

Total fare of whole journey = (x + 12y) + (x + 15y)

= 2x + 27y.

Hence, total fare = ₹ (2x + 27y).

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