Case Study
The length, breadth and height of Kavita's bedroom are 6 m, 4 m and 3 m respectively. It has two equal windows, each of dimensions 1 m × 0.5 m. It also has a door of dimensions 2 m × 1 m.
Based on the above information, answer the following questions:
Area occupied by the door and the two windows is :
(a) 1 m²
(b) 2 m²
(c) 2.5 m²
(d) 3 m²
Kavita wants to whitewash the four walls of the room. Area to be whitewashed is :
(a) 60 m²
(b) 57 m²
(c) 55 m²
(d) 50 m²
Square tiles each of side 50 cm are laid on the floor of the room. The number of such tiles laid is :
(a) 100
(b) 98
(c) 96
(d) 72
Volume of air contained in the room is :
(a) 72 m³
(b) 70 m³
(c) 60 m³
(d) 52 m³
The length of the longest rod (to the nearest m) that can be placed in the room is :
(a) 4 m
(b) 5 m
(c) 8 m
(d) 7 m

Question

Case Study
The length, breadth and height of Kavita's bedroom are 6 m, 4 m and 3 m respectively. It has two equal windows, each of dimensions 1 m × 0.5 m. It also has a door of dimensions 2 m × 1 m.

The length, breadth and height of Kavita's bedroom are 6 m, 4 m and 3 m respectively. It has two equal windows, each of dimensions 1 m × 0.5 m. It also has a door of dimensions 2 m × 1 m. Volume and Surface Area of Solids, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Based on the above information, answer the following questions:

Area occupied by the door and the two windows is :
(a) 1 m²
(b) 2 m²
(c) 2.5 m²
(d) 3 m²
Kavita wants to whitewash the four walls of the room. Area to be whitewashed is :
(a) 60 m²
(b) 57 m²
(c) 55 m²
(d) 50 m²
Square tiles each of side 50 cm are laid on the floor of the room. The number of such tiles laid is :
(a) 100
(b) 98
(c) 96
(d) 72
Volume of air contained in the room is :
(a) 72 m³
(b) 70 m³
(c) 60 m³
(d) 52 m³
The length of the longest rod (to the nearest m) that can be placed in the room is :
(a) 4 m
(b) 5 m
(c) 8 m
(d) 7 m

KnowledgeBoat · Accepted Answer

Given, Length (l) = 6 m Breadth (b) = 4 m Height (h) = 3 m Dimension of each window = 1 m × 0.5 m Dimension of door = 2 m × 1 m 1\. Area of one window = 1 × 0.5 = 0.5 m2 ∴ Area of two windows = 2 (1 × 0.5) = 1 m2 Area of one door = 2 × 1 = 2 m2. Total area = 2 + 1 = 3 m2. Hence, option (d) is the correct option. 2\. Area to be whitewashed = Area of four walls - Area of two windows and a door. Calculating the area of four walls, We know that, Area of four walls = 2h(l + b) = 2 × 3 × (6 + 4) = 6 × 10 = 60 m2. Area of two windows and a door = 3 m2. Area to be whitewashed = 60 - 3 = 57 m2. Hence, option (b) is the correct option. 3\. Given, Tile side = 50 cm = 0.5 m Calculating the floor area, Area of floor = Length × Breadth = 6 × 4 = 24 m2. Area of square tile = (side)2 = (0.5)2 = 0.25 m2 Number of tiles = = = 96. Hence, option (c) is the correct option. 4\. Volume of air contained in the room = l × b × h = 6 × 4 × 3 = 72 m3. Hence, option (a) is the correct option. 5\. Length of the longest rod that can be placed in the room = Diagonal of room Hence, option (c) is the correct option.

Mathematics

Mensuration

Related Questions

The sum of the length, breadth and height of a cuboid is 41 cm. If the length of its diagonal is 25 cm, then its total surface area is :
1050 cm²
1052 cm²
1054 cm²
1056 cm²

Mathematics

Mensuration

Related Questions

The sum of the length, breadth and height of a cuboid is 41 cm. If the length of its diagonal is 25 cm, then its total surface area is :1050 cm21052 cm21054 cm21056 cm2

The sum of the length, breadth and height of a cuboid is 41 cm. If the length of its diagonal is 25 cm, then its total surface area is :
1050 cm²
1052 cm²
1054 cm²
1056 cm²