Case study:
In a school chemistry lab, the lab assistant has two bottles of acid solution on his shelf:
Solution A: 55% acid concentration
Solution B: 80% acid concentration
The science teacher wants a 60% acid solution for tomorrow’s experiment that is to be used by the students.
In what ratio should the 55% solution and the 80% solution be mixed to obtain a 60% acid solution?

Question

Case study:
In a school chemistry lab, the lab assistant has two bottles of acid solution on his shelf:

Solution A: 55% acid concentration

Solution B: 80% acid concentration

The science teacher wants a 60% acid solution for tomorrow’s experiment that is to be used by the students.

In what ratio should the 55% solution and the 80% solution be mixed to obtain a 60% acid solution?

KnowledgeBoat · Accepted Answer

Let x be the quantity of 55% solution and y be the quantity of 80% solution. Required concentration of solution by mixing two solutions = 60%. 55x + 80y = 60(x + y) ⇒ 55x + 80y = 60x + 60y ⇒ 55x - 60x + 80y - 60y = 0 ⇒ -5x + 20y = 0 ⇒ 20y = 5x ⇒ ⇒ ⇒ x : y = 4 : 1. Hence, the ratio of 55% solution to 80% solution is 4 : 1.

Mathematics

Ratio Proportion

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