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Mathematics

A certain sum of money amounts to ₹ 4,500 in first year; to ₹ 5,175 in second year and to ₹ 6,210 in third year.Find the rate of interest for the (i) second year (ii) third year.

Compound Interest

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Answer

(i) Given: Amount at the end of the first year = ₹ 4,500

Amount at the end of the second year = ₹ 5,175

Amount at the end of the third year = ₹ 6,210

Interest for second year = ₹ 5,175 - ₹ 4,500 = ₹ 675

For the second year:

P = ₹ 4,500, R = R %, T = 1 year, I = ₹ 675

Interest=P×R×T100675=4,500×R×1100R=675×1004,500R=15\text{Interest} = \dfrac{P \times R \times T}{100}\\[1em] \Rightarrow 675 = \dfrac{4,500 \times R \times 1}{100}\\[1em] \Rightarrow R = \dfrac{675 \times 100}{4,500}\\[1em] \Rightarrow R = 15%

Hence, the rate of interest for second year = 15%.

(ii) Interest for third year = ₹ 6,210 - ₹ 5,175 = ₹ 1,035

For the third year:

P = ₹ 5,175, R = R %, T = 1 year, I = ₹ 1,035

Interest=P×R×T1001,035=5,175×R×1100R=1,035×1005,175R=20\text{Interest} = \dfrac{P \times R \times T}{100}\\[1em] \Rightarrow 1,035 = \dfrac{5,175 \times R \times 1}{100}\\[1em] \Rightarrow R = \dfrac{1,035 \times 100}{5,175}\\[1em] \Rightarrow R = 20%

Hence, the rate of interest for third year = 20%.

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