A seconds' pendulum is taken to a place where acceleration due to gravity falls to one forth. How is the time period of the pendulum affected, if at all? Give reason. What will be its new time period?

Find the length of a seconds' pendulum at a place where g = 10 ms^-2 (Take π = 3.14).

A pendulum completes 2 oscillations in 5s.

(a) What is its time period?

(b) If g = 9.8 ms^-2, find its length.

The time periods of two simple pendulums at a place are in the ratio 2:1. What will be the ratio of their lengths ?