Compute:
[132]−25\Big[\dfrac{1}{32}\Big]^{-\dfrac{2}{5}}[321]−52
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[132]−25=[1525]−25=[12]−5×25=[12]−2=[21]2=[2×21×1]=41=4\Big[\dfrac{1}{32}\Big]^{-\dfrac{2}{5}}\\[1em] = \Big[\dfrac{1^5}{2^5}\Big]^{-\dfrac{2}{5}}\\[1em] = \Big[\dfrac{1}{2}\Big]^{-5 \times \dfrac{2}{5}}\\[1em] = \Big[\dfrac{1}{2}\Big]^{-2}\\[1em] = \Big[\dfrac{2}{1}\Big]^2\\[1em] = \Big[\dfrac{2 \times 2}{1 \times 1}\Big]\\[1em] = \dfrac{4}{1}\\[1em] = 4[321]−52=[2515]−52=[21]−5×52=[21]−2=[12]2=[1×12×2]=14=4
[132]−25=4\big[\dfrac{1}{32}\Big]^{-\dfrac{2}{5}} = 4[321]−52=4
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