Compute:
[5628]0÷[25]3×1625\Big[\dfrac{56}{28}\Big]^0 ÷ \Big[\dfrac{2}{5}\Big]^3 \times \dfrac{16}{25}[2856]0÷[52]3×2516
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[5628]0÷[25]3×1625=1÷[25]3×1625 [∵a0=1]=1×[52]3×1625=[52]3×[2452]=[5323]×[2452]=53×2−3×24×5−2=(5)3−2×(2)4−3=(5)1×(2)1=10\Big[\dfrac{56}{28}\Big]^0 ÷ \Big[\dfrac{2}{5}\Big]^3 \times \dfrac{16}{25}\\[1em] = 1 ÷ \Big[\dfrac{2}{5}\Big]^3 \times \dfrac{16}{25} \space [∵ a^0 = 1] \\[1em] = 1 \times \Big[\dfrac{5}{2}\Big]^3 \times \dfrac{16}{25}\\[1em] = \Big[\dfrac{5}{2}\Big]^3 \times \Big[\dfrac{2^4}{5^2}\Big]\\[1em] = \Big[\dfrac{5^3}{2^3}\Big] \times \Big[\dfrac{2^4}{5^2}\Big]\\[1em] = 5^3 \times 2^{-3} \times 2^4 \times 5^{-2} \\[1em] = (5)^{3-2} \times (2)^{4-3}\\[1em] = (5)^{1} \times (2)^{1}\\[1em] = 10[2856]0÷[52]3×2516=1÷[52]3×2516 [∵a0=1]=1×[25]3×2516=[25]3×[5224]=[2353]×[5224]=53×2−3×24×5−2=(5)3−2×(2)4−3=(5)1×(2)1=10
[5628]0÷[25]3×1625=10\Big[\dfrac{56}{28}\Big]^0 ÷ \Big[\dfrac{2}{5}\Big]^3 \times \dfrac{16}{25} = 10[2856]0÷[52]3×2516=10
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