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Mathematics

Compute:

(47)2×(43)4(4^7)^2 \times (4^{-3})^4

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Answer

(47)2×(43)4=(4)7×2×[14]3×4=(4)14×[14]12=(4)14×(4)12=(4)1412=42=16(4^7)^2 \times (4^{-3})^4\\[1em] = (4)^{7 \times 2} \times \Big[\dfrac{1}{4}\Big]^{3 \times 4}\\[1em] = (4)^{14} \times \Big[\dfrac{1}{4}\Big]^{12}\\[1em] = (4)^{14} \times (4)^{-12}\\[1em] = (4)^{14-12} \\[1em] = 4^2 \\[1em] = 16

Hence, (47)2×(43)4=16(4^7)^2 \times (4^{-3})^4 = 16

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