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Mathematics

Consider the following distribution :

ClassFrequency
0 – 2017
20 – 4028
40 – 6032
60 – 80f
80 – 10019

If the mean of the above distribution is 50, what is the value of f ?

  1. 24

  2. 34

  3. 56

  4. 96

Measures of Central Tendency

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Answer

ClassFrequency (fi)Class mark (xi)fixi
0 – 201710170
20 – 402830840
40 – 6032501600
60 – 80f7070f
80 – 10019901710
Total∑ fi = 96 + f∑ fixi = 4320 + 70f

By formula,

Mean=fixifi50=4320+70f96+f50(96+f)=4320+70f4800+50f=4320+70f48004320=70f50f480=20ff=48020f=24.\Rightarrow \text{Mean} = \dfrac{\sum fi xi}{\sum f_i} \\[1em] \Rightarrow 50 = \dfrac{4320 + 70f}{96 + f} \\[1em] \Rightarrow 50(96 + f) = 4320 + 70f \\[1em] 4800 + 50f = 4320 + 70f \\[1em] \Rightarrow 4800 - 4320 = 70f - 50f \\[1em] \Rightarrow 480 = 20f \\[1em] \Rightarrow f = \frac{480}{20} \\[1em] \Rightarrow f = 24.

Hence, option 1 is the correct option.

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