Consider the following table:

Class	Frequency
0 - 5	8
5 - 10	10
10 - 15	19
15 - 20	25
20 - 25	8

The upper limit of the median class is :

1. 10

2. 15

3. 20

4. 25

We construct the cumulative frequency distribution table as under :

Here n = 70, which is even.

By formula,

Median = $\dfrac{\dfrac{\text{n}}{2} \text{ th observation} + \Big(\dfrac{\text{n}}{2} + 1\Big) \text{ th observation}}{2}$

$= \dfrac{\dfrac{70}{2} \text{ th observation} + \Big(\dfrac{70}{2} + 1\Big) \text{ th observation}}{2} \\[1em] = \dfrac{35 \text{ th observation} + \Big(35 + 1\Big) \text{ th observation}}{2} \\[1em] = \dfrac{35 \text{th observation} + 36 \text{ th observation}}{2}$

As observation from 19th to 37th lies in the class 10 - 15

∴ Median class = 10 - 15, with upper limit = 15

Hence, Option 2 is the correct option.