KnowledgeBoat Logo
|

Mathematics

Construct a frequency polygon for the following distribution :

Class-intervals0 - 44 - 88 - 1212 - 1616 - 2020 - 24
Frequency471015116

Statistics

49 Likes

Answer

Class intervalsFrequencyClass mark
-4 - 00−4+02=−2\dfrac{-4 + 0}{2} = -2
0 - 440+42=2\dfrac{0 + 4}{2} = 2
4 - 874+82=6\dfrac{4 + 8}{2} = 6
8 - 12128+122=10\dfrac{8 + 12}{2} = 10
12 - 161512+162=14\dfrac{12 + 16}{2} = 14
16 - 201116+202=18\dfrac{16 + 20}{2} = 18
20 - 24620+242=22\dfrac{20 + 24}{2} = 22
24 - 28024+282=26\dfrac{24 + 28}{2} = 26

Steps:

  1. Find the class-mark (mid-value) of each given class-interval.

    Class-mark = mid-value = Upper limit + Lower limit2\dfrac{\text{Upper limit + Lower limit}}{2}

  2. On a graph paper, mark class-marks along x-axis and frequencies along y-axis.

  3. On this graph paper, mark points taking values of class-marks along x-axis and the values of their corresponding frequencies along y-axis.

  4. Draw line segments joining the consecutive points marked in step (3) above.

Construct a frequency polygon for the following distribution : Statistics, Concise Mathematics Solutions ICSE Class 9.

Answered By

32 Likes

Related Questions