Mathematics
(i) Construct a ΔABC in which BC = 5 cm, AB = 6.5 cm and ∠ABC = 120°.
(ii) Construct a circle circumscribing ΔABC.
(iii) Draw a cyclic quadrilateral ABCD so that D is equidistant from B and C.
Answer
Steps of construction :
Draw a line segment BC = 5 cm.
From B construct angle 120° and extend the line such that AB = 6.5 cm.
Join points A, B and C. Hence, the △ABC is formed.
Draw the perpendicular bisector of AB and BC. Let these bisectors meet at the point O.
With O as center and radius equal to OA, draw a circle. The circle so drawn passes through the points A, B and C, and is required circumcircle of △ABC.
Extend perpendicular bisector of BC, until it intersect circle and mark it as D.
Join AD and CD.
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