Mathematics
Construct a frequency distribution table from the following cumulative frequency distribution:
| Class-Interval | Cumulative Frequency |
|---|---|
| 0 – 8 | 8 |
| 8 – 16 | 21 |
| 16 – 24 | 26 |
| 24 – 32 | 33 |
| 32 – 40 | 42 |
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Answer
Frequency = Current C.F - Previous C.F
Frequency distribution table :
| Class Interval | Frequency | Cumulative Frequency |
|---|---|---|
| 0 – 8 | 8 | 8 |
| 8 – 16 | 13 (21 - 8) | 21 |
| 16 – 24 | 5 (26 - 21) | 26 |
| 24 – 32 | 7 (33 - 26) | 33 |
| 32 – 40 | 9 (42 - 33) | 42 |
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The marks obtained by 35 students in an examination are given below :
370, 290, 318, 175, 170, 410, 378, 405, 380, 375, 315, 305, 325, 275, 241, 288, 261, 355, 402, 380, 178, 253, 428, 240, 210, 175, 154, 405, 380, 370, 306, 460, 328, 440, 425
Form cumulative frequency table with class intervals of length 50.
Construct the cumulative frequency table from the frequency table given below:
Class-Interval Frequency 0 – 6 7 6 – 12 11 12 – 18 8 18 – 24 14 24 – 30 12 Construct a frequency table from the following data :
Age (in years) Number of Students Less than 10 6 Less than 20 14 Less than 30 30 Less than 40 52 Less than 50 65 Less than 60 70 Convert the following frequency distribution to exclusive form :
Class Interval Frequency 30 – 34 7 35 – 39 9 40 – 44 13 45 – 49 6 50 – 54 3 55 – 59 10 Use this table to find :
(i) The true class-limits of the fourth class-interval.
(ii) The class-boundaries of the fifth class-interval.
(iii) The class-mark of the third class-interval.
(iv) The class-size of the sixth class-interval.