Mathematics
Construct a frequency polygon from the following data :
| Class-interval | Frequency |
|---|---|
| 1 - 5 | 5 |
| 6 - 10 | 8 |
| 11 - 15 | 12 |
| 16 - 20 | 7 |
| 21 - 25 | 4 |
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Answer
The following frequency distribution table is discontinuous. Convert it into continuous frequency distribution.
Adjustment factor =
= = 0.5.
Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.
Continuous frequency distribution table :
| Class-interval | Class mark | Frequency |
|---|---|---|
| 0.5 - 5.5 | 3 | 5 |
| 5.5 - 10.5 | 8 | 8 |
| 10.5 - 15.5 | 13 | 12 |
| 15.5 - 20.5 | 18 | 7 |
| 20.5 - 25.5 | 23 | 4 |
Steps to draw frequency polygon :
Take 2 cm along x-axis = 5 units.
Take 2 cm along y-axis = 2 units.
Find the mid-point of class intervals.
A kink is drawn near x-axis to show that the scale begins at 0.5.
Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.
Join consecutive points by line segments.
Join first end point with mid-point of class -5.5 - 0.5 with zero frequency and join the other end with mid-point of class 25.5 - 30.5 with zero frequency.
The required frequency polygon is shown below:

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