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Mathematics

Construct a frequency polygon from the following data :

Class-intervalFrequency
1 - 55
6 - 108
11 - 1512
16 - 207
21 - 254

Statistics

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Answer

The following frequency distribution table is discontinuous. Convert it into continuous frequency distribution.

Adjustment factor = Lower limit of one class - Upper limit of previous class2\dfrac{\text{Lower limit of one class - Upper limit of previous class}}{2}

= 652=12\dfrac{6 - 5}{2} = \dfrac{1}{2} = 0.5.

Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Continuous frequency distribution table :

Class-intervalClass markFrequency
0.5 - 5.535
5.5 - 10.588
10.5 - 15.51312
15.5 - 20.5187
20.5 - 25.5234

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 5 units.

  2. Take 2 cm along y-axis = 2 units.

  3. Find the mid-point of class intervals.

  4. A kink is drawn near x-axis to show that the scale begins at 0.5.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class -5.5 - 0.5 with zero frequency and join the other end with mid-point of class 25.5 - 30.5 with zero frequency.

The required frequency polygon is shown below:

Join first end point with mid-point of class -5.5 - 0.5 with zero frequency and join the other end with mid-point of class 25.5 - 30.5 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

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