Mathematics
Construct a frequency table for the following ages (in years) of 30 students using equal class-intervals, one of them being 9-12, where 12 is not included.
18, 12, 7, 6, 11, 15, 21, 9, 8, 13, 15, 17, 22, 19, 14, 21, 23, 8, 12, 17, 15, 6, 18, 23, 22, 16, 9, 21, 11, 16
Statistics
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Answer
Given class is 9 - 12 (12 is not included)
so class size = 12 - 9 = 3
Minimum age = 6
Maximum age = 23
So the class intervals will be
6 - 9, 9 - 12, 12 - 15, 15 - 18, 18 - 21, 21 - 24
Frequency distribution table :
| Ages (Class Interval) | Tally-Marks | Frequency |
|---|---|---|
| 6 – 9 | 5 | |
| 9 – 12 | IIII | 4 |
| 12 – 15 | IIII | 4 |
| 15 – 18 | 7 | |
| 18 – 21 | III | 3 |
| 21 – 24 | 7 | |
| Total | 30 |
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