Chemistry
Convert dil. H2SO4 to –
(i) Hydrogen
(ii) Carbon dioxide
(iii) Sulphur dioxide
(iv) Hydrogen sulphide
(v) An acid salt
(vi) A normal salt.
Sulphuric Acid
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Answer
(i) Zn + H2SO4 (dil.) ⟶ ZnSO4 + H2 (g)
(ii) 2KHCO3 + H2SO4 ⟶ K2SO4 + 2H2O + 2CO2
(iii) S + 2H2SO4 (conc.) ⟶ 3SO2 + 2H2O
(iv) FeS + H2SO4 (dil.) ⟶ FeSO4 + H2S
(v) NaOH + H2SO4 (dil.)⟶ NaHSO4 + H2O
(vi) 2NaOH + H2SO4 (dil.)⟶ Na2SO4 + 2H2O
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Related Questions
State the basic steps with reasons, involved in diluting a beaker of conc. H2SO4.
Give reasons why dilute sulphuric acid:
(i) behaves as an acid when dilute.
(ii) is dibasic in nature.
Give equations for formation of two different acids from conc. H2SO4. State the property of sulphuric acid involved in the above formation.
Give equations for oxidation of conc. H2SO4 giving the oxidised products –
(i) Carbon dioxide
(ii) Sulphur dioxide
(iii) Phosphoric acid
(iv) Copper (II) sulphate
(v) Iodine
(vi) Sulphur
respectively