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Mathematics

Convert the following frequency distribution to exclusive form :

Class IntervalFrequency
30 – 347
35 – 399
40 – 4413
45 – 496
50 – 543
55 – 5910

Use this table to find :

(i) The true class-limits of the fourth class-interval.

(ii) The class-boundaries of the fifth class-interval.

(iii) The class-mark of the third class-interval.

(iv) The class-size of the sixth class-interval.

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Answer

Adjustment factor

= Lower limit of one class - Upper limit of previous class2=35342=12\dfrac{\text{Lower limit of one class - Upper limit of previous class}}{2} = \dfrac{35 - 34}{2} = \dfrac{1}{2} = 0.5

Subtract the lower limit of each class by 0.5 and add 0.5 to upper limit of each class.

Class IntervalExclusive Class IntervalFrequency
30 - 3429.5 - 34.57
35 - 3934.5 - 39.59
40 - 4439.5 - 44.513
45 - 4944.5 - 49.56
50 - 5449.5 - 54.53
55 - 5954.5 - 59.510

(i) The true class limits of the fourth class interval is 44.5 - 49.5.

(ii) The class-boundaries of the fifth class interval is 49.5 - 54.5.

(iii) The class-mark of the third class interval

= 39.5+44.52\dfrac{39.5 + 44.5}{2}

= 842\dfrac{84}{2}

= 42.

Hence, the class mark of third class interval = 42.

(iv) Sixth class interval : 54.5 - 59.5

Class size = Upper limit - lower limit

Class size = 59.5 - 54.5 = 5.

Hence, the class size of sixth class interval is 5.

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