Convert the following into a vulgar fraction :

${0.\overline{8}}$

Let $x = 0.\overline{8}$. Then,

x = 0.8888… (i)

⇒ 10x = 8.8888… (ii)

On subtracting (i) from (ii), we get:

$9x = 8 \\[1em] \Rightarrow x = \dfrac{8}{9}$

Hence, $0.\overline{8} = \dfrac{8}{9}$