Convert the following into exponential form:

(i) log₂32 = 5

(ii) log₃81 = 4

(iii) log₃$\dfrac{1}{3}$ = -1

(iv) log₈4 = $\dfrac{2}{3}$

(v) log₈32 = $\dfrac{5}{3}$

(vi) log₁₀ (0.001) = -3

(vii) log₂ 0.25 = -2

(viii) log_a $\Big(\dfrac{1}{a}\Big)$ = -1

(i) log₂32 = 5

⇒ 2⁵ = 32

(ii) log₃81 = 4

⇒ 3⁴ = 81

(iii) log₃$\dfrac{1}{3}$ = -1

⇒ 3^-1 = $\dfrac{1}{3}$

(iv) log₈4 = $\dfrac{2}{3}$

⇒ $(8)^{\dfrac{2}{3}}$ = 4

(v) log₈ 32 = $\dfrac{5}{3}$

⇒ $(8)^{\dfrac{5}{3}} = 32$

(vi) log₁₀ (0.001) = -3

⇒ 10^-3 = 0.001

(vii) log₂ 0.25 = -2

⇒ (2)^-2 = 0.25

(viii) log_a $\Big(\dfrac{1}{a}\Big)$ = -1

⇒ a^-1 = $\dfrac{1}{a}$.