The centroid of the triangle whose vertices are (-4, -2), (6, 2) and (4, 6) is :

1. (2, 2)

2. (2, 3)

3. (3, 3)

4. (0, -1)

By formula,

Centroid of triangle = $\Big(\dfrac{x$1 + x2 + x3}{3}, \dfrac{y1 + y2 + y3}{3}\Big)

Centroid of triangle ABC (G)

$= \Big(\dfrac{-4 + 6 + 4}{3}, \dfrac{-2 + 2 + 6}{3}\Big) \\[1em] = \Big(\dfrac{6}{3}, \dfrac{6}{3}\Big) \\[1em] = (2, 2).$

Hence, Option 1 is the correct option.