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Mathematics

The correct ascending order of 3,63,74\sqrt{3} , \sqrt[3]{6}, \sqrt[4]{7} is :

  1. 63,74,3\sqrt[3]{6}, \sqrt[4]{7}, \sqrt{3}

  2. 74,3,63\sqrt[4]{7}, \sqrt{3}, \sqrt[3]{6}

  3. 3,74,63\sqrt{3}, \sqrt[4]{7}, \sqrt[3]{6}

  4. 63,3,74\sqrt[3]{6}, \sqrt{3}, \sqrt[4]{7}

Rational Irrational Nos

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Answer

On solving,

3\sqrt{3} = 1.732

63\sqrt[3]{6} = 1.817

74\sqrt[4]{7} = 1.626

74<3<63\sqrt[4]{7} \lt \sqrt{3} \lt \sqrt[3]{6}

Hence, Option 2 is the correct option.

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