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Mathematics

The corresponding proportional sides with respect to the pair of similar triangles obtained above is :

  1. CDAB=OCOA=ODOB\dfrac{CD}{AB} = \dfrac{OC}{OA} = \dfrac{OD}{OB}

  2. ADBC=OCOA=ODOB\dfrac{AD}{BC} = \dfrac{OC}{OA} = \dfrac{OD}{OB}

  3. ADBC=BDAC=ABDC\dfrac{AD}{BC} = \dfrac{BD}{AC} = \dfrac{AB}{DC}

  4. ODOB=CDCB=OCOA\dfrac{OD}{OB} = \dfrac{CD}{CB} = \dfrac{OC}{OA}

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Answer

Given,

ΔAOB ∼ ΔCOD.Since the triangles are similar, the ratios of the corresponding sides are equal,

CDAB=OCOA=ODOB\dfrac{CD}{AB} = \dfrac{OC}{OA} = \dfrac{OD}{OB}

Hence, option 1 is the correct option.

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