If cos θ = 0.51, find:

(i) θ

(ii) sin θ

(iii)tan θ

(i) Given,

cos θ = 0.51

cos 59° 18' = .5105

Difference = .0005

Mean difference of 2' = .0005

θ = 59° 18' + 2' = 59° 20'.

Hence, θ = 59° 20'.

(ii) Given,

sin θ

sin 59° 18' = .8599

Mean difference of 2' = .0003

sin 59° 20' = .8599 + .0003 = 0.8602.

Hence, sin 59° 20' = 0.8602.

(iii) Given,

tan θ

tan 59° 18' = 1.6842

Mean difference of 2' = .0022

tan 59° 20' = 1.6842 + .0022= 1.6864.

Hence, tan 59° 20' = 1.6864.