If ΔABC and ΔDEF are so related that $\dfrac{AB}{FD} = \dfrac{BC}{DE} = \dfrac{CA}{EF}$, then which of the following is true?

1. ∠A = ∠E and ∠B = ∠D

2. ∠B = ∠F and ∠C = ∠D

3. ∠A = ∠F and ∠B = ∠D

4. ∠C = ∠F and ∠A = ∠D

In the given figure, PQ is parallel to TR, then by using condition of similarity:

1. $\dfrac{PQ}{RT} = \dfrac{OP}{OT} = \dfrac{OQ}{OR}$

2. $\dfrac{PQ}{RT} = \dfrac{OP}{OR} = \dfrac{OQ}{OT}$

3. $\dfrac{PQ}{RT} = \dfrac{OR}{OP} = \dfrac{OQ}{OT}$

4. $\dfrac{PQ}{RT} = \dfrac{OP}{OR} = \dfrac{OT}{OQ}$

In ΔABC, DE ∥ BC such that $\dfrac{AD}{DB} = \dfrac{3}{5}$. If AC = 5.6 cm, then AE = ?

1. 2.1 cm

2. 2.8 cm

3. 3.1 cm

4. 4.2 cm

In ΔABC, DE ∥ BC so that AD = (7x − 4) cm, AE = (5x − 2) cm, DB = (3x + 4) cm and EC = (3x) cm.
Then x equals:

1. 2.5

2. 3

3. 4

4. 5