Mathematics
D is a point on base BC of a ΔABC such that 2BD = DC. Prove that : ar (ΔABD) = ar (ΔABC).
Related Questions
In the given figure, a point D is taken on side BC of ΔABC and AD is produced to E, making DE = AD. Show that :
ar (ΔBEC) = ar (ΔABC).
In the given figure, AD is a median of ΔABC and P is a point on AC such that :
ar (ΔADP) : ar (ΔABD) = 2 : 3.
Find :
(i) AP : PC
(ii) ar (ΔPDC) : ar (ΔABC)
In the given figure, P is a point on side BC of ΔABC such that BP : PC = 1 : 2 and Q is a point on AP such that PQ : QA = 2 : 3. Show that :
ar (ΔAQC) : ar (ΔABC) = 2 : 5.
