Calculate the total amount of heat energy required to convert 100 g of ice at -10° C completely into water at 100° C. Specific heat capacity of ice = 2.1 J g^-1 K^-1, specific heat capacity of water = 4.2 J g^-1 K^-1, specific latent heat of ice = 336 J g^-1.

The amount of heat energy required to convert 1 kg of ice at -10° C completely to water at 100° C is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg^-1 K^-1, Specific heat capacity of water is 4200 J kg^-1 K^-1.

200 g of ice at 0° C converts into water at 0° C in 1 minute when heat is supplied to it at a constant rate. In how much time, 200 g of water at 0° C will change to 20° C? Take specific latent heat of ice = 336 J g^-1.

During exercise, the body loses heat through evaporation of sweat. If a person loses 1 kg of sweat during exercise, how much energy does the body lose through evaporation? How does the cooling effect of evaporation compare to heat loss due to specific heat capacity? (Latent heat of vaporization = 2268 × 10³ J kg⁻¹, Specific heat capacity of water = 4.2 × 10³ J kg⁻¹ K⁻¹)