Mathematics

A die is thrown 300 times and outcomes are noted as given below :
Outcomes 1 2 3 4 5 6
Frequency 50 73 55 44 45 33
When the same die is thrown once more, what is the probability of getting :
(i) 4 ?
(ii) 6 ?
(iii) 5 ?
(iv) 2 ?

Outcomes	1	2	3	4	5	6
Frequency	50	73	55	44	45	33

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Total number of trials = 50 + 73 + 55 + 44 + 45 + 33 = 300.

By formula,

Probability of an event = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of trials}}$

(i) Number of times 4 appears = 44.

∴ P(getting 4) = $\dfrac{44}{300} = \dfrac{11}{75}$ .

Hence, P(getting 4) = $\dfrac{11}{75}$ .

(ii) Number of times 6 appears = 33.

∴ P(getting 6) = $\dfrac{33}{300} = \dfrac{11}{100}$ .

Hence, P(getting 6) = $\dfrac{11}{100}$ .

(iii) Number of times 5 appears = 45.

∴ P(getting 5) = $\dfrac{45}{300} = \dfrac{3}{20}$ .

Hence, P(getting 5) = $\dfrac{3}{20}$ .

(iv) Number of times 2 appears = 73.

∴ P(getting 2) = $\dfrac{73}{300}$ .

Hence, P(getting 2) = $\dfrac{73}{300}$ .

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