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Mathematics

A die is thrown once. The probability of getting a number which has at least two factors is:

  1. 1

  2. (12)\Big(\dfrac{1}{2}\Big)

  3. (23)\Big(\dfrac{2}{3}\Big)

  4. (56)\Big(\dfrac{5}{6}\Big)

Probability

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Answer

When a die is thrown, there are 6 possible outcomes:

S = {1, 2, 3, 4, 5, 6}

Total number of outcomes = 6

Let E be the event of getting a number with at least two factors, then

E = {2, 3, 4, 5, 6}

The number of favorable outcomes to the event E = 5

∴ P(E) = Number of favorable outcomesTotal number of outcomes=56\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{5}{6}

Hence, option 4 is the correct option.

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