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Mathematics

The dimensions of a field are 15 m × 12 m. A pit 7.5 m × 6 m × 1.5 m is dug in one corner of the field and the earth removed from it, is evenly spread over the remaining area of the field. Calculate, by how much the level of the field is raised.

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Answer

Given,

Field dimension = 15 m × 12 m

Pit dimension = 7.5 m × 6 m × 1.5 m

Calculating the volume of the earth dug out,

Volume = 7.5 × 6 × 1.5

= 67.5 m3.

Calculating the remaining area,

Total area of the field = 15 × 12 = 180 m2.

Area of pit opening = 7.5 × 6 = 45 m2.

Remaining area = 180 - 45 = 135 m2.

Calculating the rise in field level,

Rise in level = Volume of earth dug outRemaining area\dfrac{\text{Volume of earth dug out}}{\text{Remaining area}}

= 67.5135\dfrac{67.5}{135}

= 0.50 m

= 0.50 × 100 = 50 cm.

Hence, rise in field level = 50 cm.

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