Mathematics
Directions :
At a courier company, a daily report of parcels received for dispatch is prepared every evening, which classifies the parcels on the basis of their weights. The report of a certain day is as under :
| Weight of parcel (in grams) (x) | Number of parcels |
|---|---|
| Below 600 | 60 |
| Below 500 | 58 |
| Below 400 | 54 |
| Below 300 | 35 |
| Below 200 | 22 |
| Below 100 | 10 |
35.How many parcels have weights in the range of 300 – 400 grams?
(a) 4
(b) 12
(c) 13
(d) 19
36.How many parcels have weights in the range of 200 – 300 grams?
(a) 10
(b) 12
(c) 13
(d) 19
37.In which of the following weight ranges, the number of parcels is the lowest?
(a) 100 – 200
(b) 200 – 300
(c) 400 – 500
(d) 500 – 600
38.The mean weight of parcels received on that particular day is :
(a) 226.78 g
(b) 251.67 g
(c) 284.28 g
(d) 302.16 g
Related Questions
Which of the following cannot be determined graphically?
Mean
Median
Mode
none of these
Directions : The marks obtained by 10 students in a class-test were as follows :
36, 64, 48, 52, 57, 73, 26, 39, 78, 67
31. The mean marks of the whole class is :
(a) 49.1
(b) 53.7
(c) 54
(d) 6032. If the maximum marks in the test were 80, the mean percentage of marks obtained by the students is :
(a) 65%
(b) 67.5%
(c) 68%
(d) 72%33. The mean marks of the top 5 scorers in the class is :
(a) 65.4
(b) 66.8
(c) 67.2
(d) 67.834. As per the Board’s instruction each student who obtained less than 50 marks was awarded 3 grace marks. The new mean of the marks thus obtained increases by :
(a) 0.9
(b) 1.2
(c) 1.5
(d) 1.8Assertion (A): If xi’s are the mid-points of the class intervals of a grouped data, Σfi’s are the corresponding frequencies and x̄ is the mean, then Σfi(xi − x̄) = 1.
Reason (R): The sum of the deviations from the mean is 0.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false