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Mathematics

Directions:

At an NCC camp, several tents were installed. Each tent is cylindrical to a height of 3 m and conical above it. The total height of the tent is 13.5 m and the radius of its base is 14 m.

Based on this information, answer the following questions:

61. The slant height of the conical portion of the tent is :

(a) 16.5 m
(b) 17.5 m
(c) 18.5 m
(d) 19.5 m

62. The cost of cloth required to make each tent at the rate of ₹ 80 per square meter is :

(a) ₹ 76560
(b) ₹ 80140
(c) ₹ 82720
(d) ₹ 85960

63. If each cadet requires 8 m2 of floor space and there are 15 tents in all how many cadets can be accommodated in the camp?

(a) 960
(b) 1155
(c) 1320
(d) 1440

64. If a tent has maximum number of cadets that it can accommodate as calculated in the above questions, what is the volume of air available to each cadet to breathe?

(a) 48 m3
(b) 52 m3
(c) 55 m3
(d) 77 m3

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Answer

Draw a ΔABC in which BC = 5.6 cm, ∠B = 45° and the median AD from A to BC is 4.5 cm. Inscribe a circle in it. Volume And Surface Area of solid RSA Mathematics Solutions ICSE Class 10.

61. Given,

Height of cylinder, h = 3 m

Total height of tent, T = 13.5 m

Height of cone, H = T - h = 13.5 - 3 = 10.5 m

Radius of base of cylinder = Radius of cone = r = 14 m

Slant height of cone be l m.

l2 = r2 + H2

⇒ l2 = 142 + 10.52

⇒ l2 = 196 + 110.25

⇒ l2 = 306.25

⇒ l = 306.25\sqrt{306.25} = 17.5 m

Hence, Option (b) is the correct option.

62. Curved surface area of tent = Curved surface area of cone + Curved surface area of cylinder

= 2πrh + πrl

= πr(2h + l)

=227×14(2×3+17.5)=22×2(6+17.5)=44×23.5=1034 m2.= \dfrac{22}{7} \times 14 (2 \times 3 + 17.5) \\[1em] = 22 \times 2(6 + 17.5) \\[1em] = 44 \times 23.5 \\[1em] = 1034 \text{ m}^2.

Given, cost of cloth required to make each tent is ₹ 80 per square meter.

⇒ Total cost = 80 × 1034 = ₹ 82720

Hence, Option (c) is the correct option.

63. The floor space of a tent is base area of cylinder.

∴ Area of base = πr2

= 227\dfrac{22}{7} × 14 × 14

= 22 × 2 × 14

= 616 m2

Given each cadet requires 8 m2 of floor space.

The number of cadets per tent = Area of basespace required per cadet=6168\dfrac{\text{Area of base}}{\text{space required per cadet}} = \dfrac{616}{8} = 77 cadets.

Given, there are 15 tents.

∴ Total number of cadets = 77 × 15 = 1155 cadets.

Hence, Option (b) is the correct option.

64. Volume of air in each tent = Volume of air in cylinder + Volume of air in cone

=πr2h+13πr2H=πr2(h+13H)=227×142(3+13×10.5)=227×196(3+3.5)=22×28×6.5=4004 m3.= π\text{r}^2\text{h} + \dfrac{1}{3}π\text{r}^2\text{H} \\[1em] = π\text{r}^2 (\text{h} + \dfrac{1}{3}\text{H}) \\[1em] = \dfrac{22}{7} \times 14^2 (3 + \dfrac{1}{3} \times 10.5) \\[1em] = \dfrac{22}{7} \times 196 (3 + 3.5) \\[1em] = 22 \times 28 \times 6.5 \\[1em] = 4004 \text{ m}^3.

Volume of air available to each cadet to breathe = Volume of air per tentCadets per tent=400477\dfrac{\text{Volume of air per tent}}{\text{Cadets per tent}} = \dfrac{4004}{77} = 52 m3.

Hence, Option (b) is the correct option.

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    Based on this information, answer the following questions:

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