Mathematics
Directions:
At an NCC camp, several tents were installed. Each tent is cylindrical to a height of 3 m and conical above it. The total height of the tent is 13.5 m and the radius of its base is 14 m.
Based on this information, answer the following questions:
61. The slant height of the conical portion of the tent is :(a) 16.5 m
(b) 17.5 m
(c) 18.5 m
(d) 19.5 m
(a) ₹ 76560
(b) ₹ 80140
(c) ₹ 82720
(d) ₹ 85960
(a) 960
(b) 1155
(c) 1320
(d) 1440
(a) 48 m3
(b) 52 m3
(c) 55 m3
(d) 77 m3
Mensuration
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Answer

61. Given,
Height of cylinder, h = 3 m
Total height of tent, T = 13.5 m
Height of cone, H = T - h = 13.5 - 3 = 10.5 m
Radius of base of cylinder = Radius of cone = r = 14 m
Slant height of cone be l m.
l2 = r2 + H2
⇒ l2 = 142 + 10.52
⇒ l2 = 196 + 110.25
⇒ l2 = 306.25
⇒ l = = 17.5 m
Hence, Option (b) is the correct option.
62. Curved surface area of tent = Curved surface area of cone + Curved surface area of cylinder
= 2πrh + πrl
= πr(2h + l)
Given, cost of cloth required to make each tent is ₹ 80 per square meter.
⇒ Total cost = 80 × 1034 = ₹ 82720
Hence, Option (c) is the correct option.
63. The floor space of a tent is base area of cylinder.
∴ Area of base = πr2
= × 14 × 14
= 22 × 2 × 14
= 616 m2
Given each cadet requires 8 m2 of floor space.
The number of cadets per tent = = 77 cadets.
Given, there are 15 tents.
∴ Total number of cadets = 77 × 15 = 1155 cadets.
Hence, Option (b) is the correct option.
64. Volume of air in each tent = Volume of air in cylinder + Volume of air in cone
Volume of air available to each cadet to breathe = = 52 m3.
Hence, Option (b) is the correct option.
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Related Questions
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A solid is in the form of a right circular cylinder with hemispherical ends. The total length of the solid is 35 cm. The diameter of the cylinder is one-fourth of its height. The surface area of the solid is :
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770 cm2
Directions:
From a solid cylinder of height 30 cm and radius 7 cm, a conical cavity of height 24 cm and of base radius 7 cm is drilled out.
Based on this information, answer the following questions:
65. The volume of the remaining solid is :(a) 2856 cm3
66. The total surface area of the remaining solid is :
(b) 3388 cm3
(c) 3672 cm3
(d) 4620 cm3(a) 1870 cm2
67. The slant height of the cut out cone is :
(b) 2024 cm2
(c) 2178 cm2
(d) 2332 cm2(a) 18 cm
68. The total surface area of the cut out cone is :
(b) 25 cm
(c) 26 cm
(d) 32 cm(a) 550 cm2
(b) 704 cm2
(c) 858 cm2
(d) 616 cm2Directions:
The surface area of a solid metallic sphere is 900 π cm2.
Based on this information, answer the following questions:
69. If the given sphere is melted and recast into 3 smaller spheres of equal volumes, then the radius of each smaller sphere is :(a) 5 cm
70. If the given sphere is cut into two hemispheres, then how much does the total surface area get increased? (Take π = 3.14) :
(b) 5 cm
(c) 5 cm
(d) 5 cm(a) no change
71. If the given sphere is melted and recast into solid right cones, each of radius 2.5 cm and height 8 cm, how many cones are formed?
(b) 706.5 cm2
(c) 1015 cm2
(d) 1413 cm2(a) 135
72. If the given sphere is melted and recast into small spheres each of radius 0.5 cm, then the number of spheres formed is :
(b) 270
(c) 405
(d) 540(a) 1350
(b) 2700
(c) 13500
(d) 27000