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Mathematics

Directions:

Three unbiased coins are tossed simultaneously.

Based on this information, answer the following questions:

55.The probability of getting at least one head is:

(a) (38)\Big(\dfrac{3}{8}\Big)

(b) (12)\Big(\dfrac{1}{2}\Big)

(c) (58)\Big(\dfrac{5}{8}\Big)

(d) (78)\Big(\dfrac{7}{8}\Big)

56.The probability of getting at least two tails is:

(a) (14)\Big(\dfrac{1}{4}\Big)

(b) (38)\Big(\dfrac{3}{8}\Big)

(c) (12)\Big(\dfrac{1}{2}\Big)

(d) (58)\Big(\dfrac{5}{8}\Big)

57.The probability of getting at most two heads is:

(a) (12)\Big(\dfrac{1}{2}\Big)

(b) (38)\Big(\dfrac{3}{8}\Big)

(c) (34)\Big(\dfrac{3}{4}\Big)

(d) (78)\Big(\dfrac{7}{8}\Big)

58.The probability of getting two tails is:

(a) (38)\Big(\dfrac{3}{8}\Big)

(b) (12)\Big(\dfrac{1}{2}\Big)

(c) (34)\Big(\dfrac{3}{4}\Big)

(d) (58)\Big(\dfrac{5}{8}\Big)

Probability

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Answer

55. When three unbiased coins are tossed simultaneously, each coin has 2 possible outcomes

Total number of outcomes = 8

Let E be the event of getting at least one head.

E = {HHH, HHT, HTH, THH, HTT, THT, TTH}

The number of favorable outcomes to the event E = 7

P(E)=Number of favorable outcomesTotal number of outcomes=78\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{7}{8}

Hence, option (d) is the correct option.

56. Total number of outcomes = 8

Let E be the event of getting at least two tails.

E = {HTT, THT, TTH, TTT}

The number of favorable outcomes to the event E = 4

P(E)=Number of favorable outcomesTotal number of outcomes=48=12\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{4}{8} = \dfrac{1}{2}

Hence, option (c) is the correct option.

57. Total number of outcomes = 8

Let E be the event of getting at most two heads.

E = {HHT, HTH, THH, HTT, THT, TTH, TTT}

The number of favorable outcomes to the event E = 7

P(E)=Number of favorable outcomesTotal number of outcomes=78\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{7}{8}

Hence, option (d) is the correct option.

58. Total number of outcomes = 8

Let E be the event of getting exactly two tails.

E = {HTT, THT, TTH}

The number of favorable outcomes to the event E = 3

P(E)=Number of favorable outcomesTotal number of outcomes=38\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{3}{8}

Hence, option (a) is the correct option.

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