The discriminant of the equation, 3x^2 - 2x + 1/3 = 0 is : 1. 0 2. 1 3. 2 4. 4

Comparing 3x2 - 2x + = 0 with ax2 + bx + c = 0 we get, a = 3, b = -2 and c = . We know that, ⇒ D = b2 - 4ac ⇒ D = (-2)2 - 4(3) ⇒ D = 4 - 4 ⇒ D = 0. Hence, option 1 is the correct option.

Mathematics

The discriminant of the equation, 3x² - 2x + $\dfrac{1}{3}$ = 0 is :
0
1
2
4

Quadratic Equations

2 Likes

Answer

Comparing 3x² - 2x + $\dfrac{1}{3}$ = 0 with ax² + bx + c = 0 we get,

a = 3, b = -2 and c = $\dfrac{1}{3}$ .

We know that,

⇒ D = b² - 4ac

⇒ D = (-2)² - 4(3) $\Big(\dfrac{1}{3}\Big)$

⇒ D = 4 - 4

⇒ D = 0.

Hence, option 1 is the correct option.

Answered By

2 Likes

Mathematics

The discriminant of the equation, 3x² - 2x + $\dfrac{1}{3}$ = 0 is :
0
1
2
4

Quadratic Equations

Answer

Related Questions

The solution set for the quadratic equation 2x² + kx - k² = 0 is:
{k, k}
{-k, k}
$\Big{-k, \dfrac{k}{2}\Big}$
$\Big{\dfrac{-k}{2}, k\Big}$

The solution set for the equation, 25x(x + 1) = -4, is:
$\Big{\dfrac{1}{5}, \dfrac{4}{5}\Big}$
$\Big{-\dfrac{1}{5}, \dfrac{4}{5}\Big}$
$\Big{-\dfrac{4}{5}, -\dfrac{1}{5}\Big}$
$\Big{-\dfrac{4}{5}, \dfrac{1}{5}\Big}$

The value of the discriminant of the equation, $\sqrt{3}x^2 + 10x + 7\sqrt{3}$ = 0 is:
4
16
-16
-12

The value of the discriminant of the equation, x² - ( $\sqrt{2}$ + 1)x + $\sqrt{2}$ = 0 is:
3 + $2\sqrt{2}$
1 - $2\sqrt{2}$
3 - $2\sqrt{2}$
2 - $\sqrt{2}$

Mathematics

The discriminant of the equation, 3x2 - 2x + 13\dfrac{1}{3}31​ = 0 is :0124

Quadratic Equations

Answer

Related Questions

The solution set for the quadratic equation 2x2 + kx - k2 = 0 is:{k, k}{-k, k}{−k,k2}\Big{-k, \dfrac{k}{2}\Big}{−k,2k​}{−k2,k}\Big{\dfrac{-k}{2}, k\Big}{2−k​,k}

The value of the discriminant of the equation, 3x2+10x+73\sqrt{3}x^2 + 10x + 7\sqrt{3}3​x2+10x+73​ = 0 is:416-16-12

The value of the discriminant of the equation, x2 - (2\sqrt{2}2​ + 1)x + 2\sqrt{2}2​ = 0 is:3 + 222\sqrt{2}22​1 - 222\sqrt{2}22​3 - 222\sqrt{2}22​2 - 2\sqrt{2}2​

The discriminant of the equation, 3x² - 2x + $\dfrac{1}{3}$ = 0 is :
0
1
2
4

The solution set for the quadratic equation 2x² + kx - k² = 0 is:
{k, k}
{-k, k}
$\Big{-k, \dfrac{k}{2}\Big}$
$\Big{\dfrac{-k}{2}, k\Big}$

The value of the discriminant of the equation, $\sqrt{3}x^2 + 10x + 7\sqrt{3}$ = 0 is:
4
16
-16
-12

The value of the discriminant of the equation, x² - ( $\sqrt{2}$ + 1)x + $\sqrt{2}$ = 0 is:
3 + $2\sqrt{2}$
1 - $2\sqrt{2}$
3 - $2\sqrt{2}$
2 - $\sqrt{2}$