Mathematics
Discuss the nature of the roots of the following equation without actually solving it:
9x2 - 6x + 1 = 0
Quadratic Equations
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Answer
Comparing 9x2 - 6x + 1 = 0 with ax2 + bx + c = 0 we get,
a = 9, b = -6 and c = 1.
We know that,
Discriminant (D) = b2 - 4ac = (-6)2 - 4 × 9 × 1
= 36 - 36 = 0.
Hence, the roots are rational and equal.
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